2u^2-15u+22=(u-4)^2

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Solution for 2u^2-15u+22=(u-4)^2 equation: 



2u^2-15u+22=(u-4)^2

We move all terms to the left:

2u^2-15u+22-((u-4)^2)=0



We calculate terms in parentheses: -((u-4)^2), so:

(u-4)^2





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(u-4)^2





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(u-4)^2





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(u-4)^2





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(u-4)^2





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(u-4)^2





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(u-4)^2





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(u-4)^2





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(u-4)^2





We calculate terms in parentheses: -((u-4)^2), so:

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We calculate terms in parentheses: -((u-4)^2), so:

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We calculate terms in parentheses: -((u-4)^2), so:

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